OSI LAYER MODEL: Data Transfer From Student's Computer to Ulearn System Server Which is in the UTeM IT Center
What is OSI Model?
Open Systems Interconnection (OSI) Model is a model which describe seven layers of communication over a network between computer systems. It was the first standard modal for network communications, adopted by all major computer and telecommunication companies in the early 1980s.
The modern internet is now based on the simpler TCP/IP Model, not on OSI Model. However, the OSI Model is still widely used because it can help to visualize and communicate the operation of networks. It also helps in the isolation and troubleshooting of networking problems.
OSI Layer Model
Responsibilities of Each Layer:
- Application Layer
- Presentation Layer
- Session Layer
- Transport Layer
- Network Layer
- Data Link Layer
- Physical Layer
From Student's Computer:
- Application Layer
- Presentation Layer
- Session Layer
- Transport Layer
The
transport layer receives the data from the upper layer and performs
segmentation. The source and destination port numbers will
include in the header file of the data before forwarding it to the network layer.
- Network Layer
- Data Link Layer
- Physical Layer
To Ulearn System Server:
- Physical Layer
- Data Link Layer
- Network Layer
The network layer is not needed when both the systems are connected to the same link. It then reassembles the data packets into segments for the upper layer.
- Transport Layer
In this layer, the transport layer will perform the reassembly and sequencing of data. It reads the
port number of the data from the header file and then directs it toward the
proper application.
- Session Layer
- Presentation Layer
- Application Layer
Subnetting Calculation
In this section, you are expecting to show the calculation on how to identify the IP address that was assigned for the Ulearn System Server based on the information given in the project scenario. Explain the concept and show the calculation to identify the IP address.
In term of private addressing scheme, UTeM network is using Class C private addressing scheme which is 192.168.1.0/24. At UTeM, there are 8 different faculty. Hence, the network address was segregated by using subnetting concept. Each faculty member is given their network address. Assign IT Center as another subnet with their network address. From this network address, assigned as the 5th available address as the address of the Ulearn System Server.
Assume that IT Center is being assigned as the 5th available subnet as their network address.
For UTeM network, it uses Class C private addressing scheme: 192.168.1.0/24
Subnetting to 8 faculties
So, in this case, we will use 23 as our number of host bits borrowed as 8 fulfils our requirement.
3 bits need to be borrowed from the Host
Old |
192 |
168 |
1 |
0 |
/24 |
New |
192 |
168 |
1 |
NNNHHHHH |
/27 |
N = network bit , H = host bit
255.255.255.224 is the new subnet mask. We get 224 by adding 128, 64, and 32 since we borrow 3 bits from the host.
Possible
Number of Hosts per Subnets
To calculate the number of
possible hosts per subnet, use the formula 2^n -2, where h equals the number of
host bits. Two addresses must be subtracted because of the network address and
the broadcast address.
Determine the number of remaining host bits based on the class of address and the number of host bits borrowed.
New Netwok Number |
192.168.1.0/27 |
New Subnet Mask |
255.255.255.224 |
Class Type |
C |
Number of Host Bits Available |
8 |
Number of Host Bits
Borrowed |
3 |
Number of Host Bits
Remaining (n) |
8-3 =5 |
Number of Hosts per Subnet |
= 2n– 2 = 25-2 =32 -2 =30
|
New Prefix |
/27 |
Number of Usable Host per Subnet |
= 23- 2 =30 |
Subnet number |
Network ID |
Host ID Range |
Broadcast Address |
0 |
192.168.1.0/27 |
192.168.1.1/27 To 192.168.1.30/27 |
192.168.1.31/27 |
1 |
192.168.1.32/27 |
192.168.1.33/27 To 192.168.1.62/27 |
192.168.1.63/27 |
2 |
192.168.1.64/27 |
192.168.1.65/27 To 192.168.1.94/27 |
192.168.1.95/27 |
3 |
192.168.1.96/27 |
192.168.1.97/27 To 192.168.1.126/27 |
192.168.1.127/27 |
4 |
192.168.1.128/27 |
192.168.1.129/27 To 192.168.1.158/27 |
192.168.1.159/27 |
5 |
192.168.1.160/27 |
192.168.1.161/27 To 192.168.1.190/27 |
192.168.1.191/27 |
6 |
192.168.1.192/27 |
192.168.1.193/27 To 192.168.1.222/27 |
192.168.1.223/27 |
7 |
192.168.1.224/27 |
192.168.1.225/27 To 192.168.1.254/27 |
192.168.1.255/27 |
Based on the
table above, at the 5th available subnet and 5th available address. We are sure that the ULearn
System server IP address is 192.168.1.166. We do not start from 192.168.1.161 because it will be set up
as router IP Address for that subnet and become default gateway. So, it should
start from 192.168.1.162 and so on.
In this section, you
are assumed have correctly identified the IP address for the Ulearn System
Server. Therefore, you must produce a manual on how to configure the IP address
on the server. You can use any operating system to demonstrate this task. The explanation
should be supported with the screenshot and appropriate explanation.
1.
Press wins + R, type Control Panel and then press ok to open
it
2.
After opening the Control Panel,
go to Network and Internet. Then click it to open.
3.
After opening the Network
and Internet, click Network and Sharing Center to open.
4.
After opening the Network
and Sharing Center , your internet connection will appear. You may use
either Wi-Fi or Ethernet. In this example, I am using hotspot as my Wi-Fi which
is HUAWEI nova 4e. Then click the Wi-Fi status.
5. Hence, click Properties.
6.
In this activity, we would like
to configure the IP address. Thus, double-click Internet Protocol Version 4 (TCP/IPV4)
to open its Properties
7.
Internet Protocol Version 4 (TCP/IPV4)
Properties will be opened. This is where e will
configure the IP address. Commonly, we will use DHCP server, and the IP address
will be obtained automatically.
8.
In order to configure the IP
address, we change the setting from Obtain an IP address automatically to
Use the following IP address. Next, we fill in the IP address for ULearn
System Server that we get from Subnetting Calculation, which is 192.168.1.166 .
9.
The Subnet Mask will be
automatically filled based on the IP address class. In this situation, The IP
address is class C, that’s why the subnet mask will be 255.255.255.0
10.
Default Gateway is an intermediary between the local network and the world wide
web. The host address usually will be the same as the IP address but different
in the 4th octet, and that number will always be the first range.So, the Default
Gateway is 192.168.1.161.
11.
For Preferred DNS Server,
commonly, we will use the same address in Default Gateway, which is 192.168.1.161.
While the Alternate DNS Server is 8.8.8.8 since we use the Google
DNS server.
12.
After completing the requirements,
click Validate setting upon exit, then click OK button
13.
After exit, a Windows
Network Diagnostics pop-up box will appear to check whether there is no problem
with the new IP address configuration or not. If no, press the close button.
14.
In a nutshell, you may test your
internet connection. If you can access any website, its means the configuration
of IP address was successful.
Comments
Post a Comment